Error: "Failed creating java C:\Program Files\Java\jre1.8.0_111\bin\server\jvm.dll " when starting Apache Tomcat for JasperSoft 6.2


Article ID: 7532


Updated On:


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The following error appears in the Apache Tomcat logs when starting Apache Tomcat for JasperSoft 6.2:

[info] [ 3120] Commons Daemon procrun ( 64-bit) started
[info] [ 3120] Running 'Tomcat8' Service...
[info] [ 2592] Starting service...
[error] [ 2592] Failed creating java C:\Program Files\Java\jre1.8.0_111\bin\server\jvm.dll
[error] [ 2592] The system cannot find the path specified.
[error] [ 2592] ServiceStart returned 1
[error] [ 2592] The system cannot find the path specified.
[info] [ 3120] Run service finished.


Java has been upgraded and the actual Java install path has been updated


CA Service Management 14.1 Cum#3 or later
JasperSoft 6.2


The following instructions apply if Tomcat is installed as a Service:

1.  Go to the server where Apache Tomcat and Jaspersoft is installed

2.  Locate the new Java install path folder

3.  Open Configure Tomcat -> Java.  (Run the Tomcat8w.exe GUI application)

4.  Update the Java Virtual Machine path to the current JRE installation folder. For example:

C:\Program Files\Java\jre1.8.0_73\bin\server\jvm.dll

5.  Start Apache Tomcat

If Tomcat is not installed as a Service, or Tomcat8w.exe is non-existent: 

One will need to modify the JAVA_HOME and JRE_HOME environment variables directly.

If only the JAVA_HOME environment variable is set, Tomcat will run under the JRE as part of the JDK specified by the JAVA_HOME variable. Therefore, we change JRE for Tomcat by updating this variable.

JAVA_HOME=C:\Program Files\Java\jre1.8.0_73

If both the JAVA_HOME and JRE_HOME environment variables are set, the JRE_HOME is preferred. Here’s an example of a valid value for the JRE_HOME variable (path on Windows):

JRE_HOME=C:\Program Files\Java\jre1.8.0_73

Additional Information

Information about the Tomcat implementation as a service (currently the only way to obtain Tomcat8w.exe) please see: