How can I find the Encryption Key in the Top Secret Security File?

Release:
Component: TSSMVS

To find the encryption key run DUMPT against module TSSMNGR4, csect TSSKTPRC,
and the encryption key is the first 16 bytes of the csect.

Here is jcl to do a DUMPT on a module and csect:                                                                
//Insert valid jobcard here                             
//STEP1    EXEC PGM=AMASPZAP,PARM=IGNIDRFULL            
//SYSPRINT DD   SYSOUT=*                                
//SYSLIB   DD   DSN=QAPRN.xxxx.yyyy.CAILIB,DISP=SHR     
//*        UNIT=SYSDA,VOL=SER=MVS010                   
 //SYSIN    DD   *                                          
 DUMP TSSMNGR4 TSSKTPRC                 

The encryption key is 16 digits and should be afer the REP 0000.
So example: it should look something like: 
NAME TSSKTPRC 
VER 0000 0000,0000,0000,0000 
REP 0000 C7E4,D5C8,C9D3,D340 
(C7E4,D5C8,C9D3,D340 would be your encryption key)


The encryption key on the security file must match the encryption key
in the TSS CAILIB. Client had run the TSSKEY job